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Kinematics

Speed & VelocityAccelerationDistance-Time GraphsSpeed-Time GraphsFree Fall
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⚠️ Common Mistakes — Kinematics (O-Level Physics)

📝 Model Answers — Kinematics

Q1 (2 marks): A car accelerates from rest to 20 m/s in 8 seconds. Calculate its acceleration.

MODEL ANSWER — 2 marks ✓
"a = (v − u) / t (1 mark for correct formula)
a = (20 − 0) / 8 = 2.5 m/s² (1 mark for correct answer with unit)"

Examiner note: Always write the formula first, substitute values clearly, and include the unit in your final answer. Missing units = 0 for that mark.

Q2 (3 marks): Describe the motion of an object shown by a velocity-time graph with: a positive gradient from 0–5s, a horizontal line from 5–10s, then a negative gradient from 10–15s reaching zero.

MODEL ANSWER — 3 marks ✓
"From 0 to 5 s: the object accelerates uniformly from rest, as shown by the constant positive gradient (1 mark). From 5 to 10 s: the object travels at constant velocity (zero acceleration), as shown by the horizontal line (1 mark). From 10 to 15 s: the object decelerates uniformly and comes to rest, as shown by the negative gradient reaching zero velocity (1 mark)."

Examiner note: For each phase, state: (1) what the motion is, and (2) what graph feature tells you this. Describing without linking to the graph earns half marks at best.

Q3 (3 marks): A ball is dropped from rest and falls 45 m before hitting the ground. Calculate the speed at which it hits the ground. (g = 10 m/s²)

MODEL ANSWER — 3 marks ✓
"Identify: u = 0, a = 10 m/s², s = 45 m, find v (1 mark for identifying variables correctly)
Using v² = u² + 2as:
v² = 0 + 2 × 10 × 45 = 900 (1 mark for correct substitution)
v = √900 = 30 m/s (1 mark for correct answer with unit)"
Two graphs side by side showing gradient equals speed on d-t graph and gradient equals acceleration on v-t graph Distance-Time Time (s) Distance Const. speed Accelerating Stationary Gradient = speed Velocity-Time Time (s) Velocity Const. v Uniform a Non-uniform a Area = distance Gradient = accel.
Motion Graphs — Distance-Time and Velocity-Time interpretation

Contents

  1. Key definitions
  2. Motion graphs
  3. Calculating motion
  4. Free fall & terminal velocity
  5. Common exam traps
Topic 2 of 12
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1. Key Definitions

Distance

Total path length travelled — scalar (no direction).

Displacement

Straight-line distance from start to finish in a specified direction — vector.

Speed

Distance travelled per unit time — scalar. Average speed = total distance ÷ total time.

Velocity

Displacement per unit time in a stated direction — vector.

Acceleration

Rate of change of velocity — vector. a = (v − u) ÷ t, unit m/s².

A negative acceleration (deceleration) means velocity is decreasing in the positive direction.

2. Motion Graphs

Distance-time graph

Shape of lineMeaning
Horizontal lineObject is stationary (distance not changing)
Straight line with positive gradientConstant speed
Curved line (gradient increasing)Accelerating
Curved line (gradient decreasing)Decelerating

Gradient of a distance-time graph = speed.

Speed-time graph

Shape of lineMeaning
Horizontal lineConstant speed (zero acceleration)
Straight line with positive gradientUniform acceleration
Straight line with negative gradientUniform deceleration
Curved lineNon-uniform (changing) acceleration

Gradient of a speed-time graph = acceleration.

Area under a speed-time graph = distance travelled.

Area calculation

For a trapezium shape: area = ½ × (sum of parallel sides) × height. For a triangle: area = ½ × base × height. Always check the axes — time is usually x, speed is y.

3. Calculating Motion

v = u + atv = final velocity (m/s) · u = initial velocity (m/s) · a = acceleration (m/s²) · t = time (s)
distance = area under speed-time graphFor uniform acceleration from u to v: distance = ½(u + v)t
Worked example

A car accelerates from rest to 24 m/s in 8 s. Find (a) acceleration, (b) distance travelled.

(a) a = (v − u) ÷ t = (24 − 0) ÷ 8 = 3 m/s²

(b) distance = ½(u + v)t = ½ × (0 + 24) × 8 = 96 m

4. Free Fall and Terminal Velocity

In free fall (no air resistance), all objects accelerate downward at g = 10 m/s² regardless of mass. This is because gravitational force is proportional to mass, but so is the resistance to acceleration (inertia).

Terminal velocity

When an object falls through a fluid (air or liquid), air resistance increases as speed increases. Eventually, air resistance equals the weight of the object — the resultant force is zero and the object falls at constant (terminal) velocity.

StageForcesMotion
Initial fallWeight > air resistanceAccelerating downward
Approaching terminal vWeight > air resistance (smaller gap)Still accelerating, but less
Terminal velocityWeight = air resistanceConstant velocity (zero acceleration)
Common mistake

At terminal velocity, students write "there is no force on the object". Wrong — there are still two forces (weight and air resistance). They are equal and opposite, so the resultant is zero and acceleration is zero.

Key Kinematics Equations
v = u + at  |  s = ut + ½at²  |  v² = u² + 2as
u = initial velocity, v = final velocity, a = acceleration, t = time, s = displacement
Must-Know for Exam

5. Common Exam Traps

Trap 1 — Gradient vs area

On a distance-time graph, gradient = speed. On a speed-time graph, gradient = acceleration AND area = distance. Students regularly mix these up.

Trap 2 — "At rest" means u = 0

If a question says "starts from rest" or "released from rest", u = 0. Always substitute u = 0 first, then solve.

Trap 3 — Direction of deceleration

Deceleration is not a negative quantity by itself — it depends on the direction chosen as positive. State clearly: "the acceleration is −3 m/s², meaning the car is decelerating at 3 m/s²."

Key Terms — Flashcard Review

Tap each card to reveal the definition.

Speed vs velocity
Speed: scalar, distance per unit time. Velocity: vector, displacement per unit time. Both in m/s.
Acceleration
Rate of change of velocity. a = (v-u)/t. Unit: m/s2. Vector quantity. Deceleration = negative acceleration.
Distance-time graph
Gradient = speed. Horizontal line = stationary. Steeper gradient = faster speed. Curved = accelerating.
Velocity-time graph
Gradient = acceleration. Area under graph = distance travelled. Horizontal = constant velocity.
SUVAT equations
s=ut+0.5at2 and v2=u2+2as. Use when acceleration is uniform (constant).
Free fall
Acceleration due to gravity g = 10 m/s2 downward (use 10 in Singapore O-Level). Air resistance ignored in free fall.

🎯 Practice Quiz — Test Yourself

8 O Level-style questions on this topic. Select an answer to see instant feedback.

Question 1 of 8
A speed-time graph shows a horizontal line. This means the object is:
Explanation: Horizontal line on a speed-time graph = speed not changing = constant speed (zero acceleration).
Question 2 of 8
What does the area under a speed-time graph represent?
Explanation: Area under speed-time graph = distance travelled. Gradient of speed-time graph = acceleration.
Question 3 of 8
A car starts from rest and reaches 20 m/s in 5 s. What is its acceleration?
Explanation: a = (v − u) / t = (20 − 0) / 5 = 4 m/s².
Question 4 of 8
At terminal velocity, the net force on a falling object is:
Explanation: At terminal velocity, weight = air resistance. Net force = 0 → acceleration = 0 → constant velocity.
Question 5 of 8
A steeper gradient on a distance-time graph means:
Explanation: Gradient of distance-time graph = speed. Steeper gradient = greater speed.
Question 6 of 8
A car accelerates from rest to 20 m/s in 5 s. Its acceleration is:
Explanation: a = (v - u) / t = (20 - 0) / 5 = 4 m/s2. The car starts from rest so u = 0.
Question 7 of 8
On a velocity-time graph, the area under the line represents:
Explanation: Area under a velocity-time graph = displacement (distance travelled). Gradient of v-t graph = acceleration. These two key facts appear in almost every kinematics exam question.
Question 8 of 8
A ball is dropped from rest and falls freely for 3 s (g = 10 m/s2). How far does it fall?
Explanation: s = ut + 0.5at2 = 0(3) + 0.5(10)(3)2 = 0 + 0.5 x 10 x 9 = 45 m. u = 0 (dropped from rest), a = 10 m/s2, t = 3 s.
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Original study notes for Singapore students. Not affiliated with MOE, SEAB or Cambridge. Use alongside your school notes and official syllabus documents.