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Sec 1 Science
Past Year Questions

50 exam-style questions — MCQ, structured and open-ended — written in the style of Singapore school CA1, CA2, SA1 and SA2 papers. Full mark-scheme answers for every question.

Note: These are original practice questions written to match the style, format and content of Singapore lower secondary school assessments. They are not reproduced from any specific school's actual paper. For actual school past papers, check your school's library or your teacher.
20MCQ
20Structured
10Open-ended
5Topics covered
🟣 MCQ (20) 🔬 Inquiry (8) 📊 Models (6) ⚗️ Matter (8) 🌿 Living (8) ⚡ Forces (8) 🎯 Mixed (12)
🟣
Multiple Choice Questions
Select the best answer. Click to check — explanation shown after.
1
MCQ
MCQ1 markInquiry

A student investigates how the length of a pendulum affects its swing time. She measures the time for 10 swings and divides by 10. Which variable is the dependent variable?

ALength of the pendulum
BMass of the pendulum bob
CTime for one swing
DNumber of swings counted
✓ Answer: C

The dependent variable is what is measured as a result of changing the independent variable. The student is measuring the time for one swing — this is what changes in response to the pendulum length. A is the IV (what she deliberately changes). B is a controlled variable. D is the method of measuring, not the variable itself.

2
MCQ
MCQ1 markMatter

Which of the following is a compound?

AAir
BWater
COxygen
DSeawater
✓ Answer: B

Water (H₂O) is a compound — it contains hydrogen and oxygen atoms chemically bonded in a fixed 2:1 ratio, and has different properties from either element. Air and seawater are mixtures (multiple substances physically combined). Oxygen is an element (only one type of atom).

3
MCQ
MCQ1 markLiving

A cell has a large central vacuole, chloroplasts and a cell wall. Which type of cell is this?

AAnimal cell from the skin
BRoot hair cell
CPalisade mesophyll cell
DRed blood cell
✓ Answer: C

The cell has all three plant-only features (cell wall, chloroplasts, large central vacuole) AND has chloroplasts — meaning it is a photosynthetic plant cell. The palisade mesophyll cell is packed with chloroplasts for photosynthesis. Root hair cells are plant cells but have no chloroplasts (they are underground — no light). Animal cells have none of these three features.

4
MCQ
MCQ1 markForces

A book of mass 2 kg rests on a shelf. The gravitational field strength is 10 N/kg. What is the weight of the book?

A2 kg
B2 N
C20 N
D20 kg
✓ Answer: C

Weight = mass × g = 2 × 10 = 20 N. Note: weight is measured in Newtons (N), not kg. A (2 kg) is the mass, not weight. B (2 N) incorrectly omits the multiplication by g. D (20 kg) uses the wrong unit.

5
MCQ
MCQ1 markMatter

Which of the following is a physical change?

ADissolving sugar in water
BBurning magnesium in oxygen
CIron rusting in moist air
DCooking an egg
✓ Answer: A

Dissolving sugar is a physical change — the sugar particles disperse in water but no new substance is formed. The sugar can be recovered by evaporating the water. B, C and D all produce new substances with different properties (magnesium oxide, iron oxide, denatured protein) and are chemical changes.

6
MCQ
MCQ1 markModels

In a line graph, what should be plotted on the x-axis?

AThe dependent variable
BThe independent variable
CThe controlled variable
DThe mean of all readings
✓ Answer: B

The independent variable (IV) always goes on the x-axis (horizontal). The dependent variable (DV) goes on the y-axis (vertical). This is because the x-axis represents what you deliberately change, and the y-axis shows how the result responds.

7
MCQ
MCQ1 markLiving

Which group of animals lays eggs and has scales and breathes using lungs as an adult?

AFish
BAmphibians
CReptiles
DBirds
✓ Answer: C

Reptiles — scales ✓, lay eggs ✓, breathe with lungs as adults ✓. Fish have scales but breathe with gills. Amphibians have moist smooth skin (no scales) and larvae breathe with gills. Birds have feathers, not scales.

8
MCQ
MCQ1 markForces

A force of 40 N acts on a surface of area 0.2 m². What is the pressure on the surface?

A8 Pa
B200 Pa
C8 N
D0.005 Pa
✓ Answer: B

P = F ÷ A = 40 ÷ 0.2 = 200 Pa. A (8 Pa) is wrong — likely from multiplying instead of dividing. C uses wrong units (N is for force, not pressure). D (0.005) is the inverse — area divided by force.

9
MCQ
MCQ1 markMatter

During which change of state does a substance release energy to its surroundings?

AMelting
BEvaporation
CSublimation
DCondensation
✓ Answer: D

Condensation (gas → liquid) releases energy. Melting, evaporation and sublimation all absorb energy (particles need energy to overcome forces and move further apart). Condensation is the reverse of evaporation — particles lose energy and come closer together.

10
MCQ
MCQ1 markLiving

In a food chain: Grass → Rabbit → Fox. If many rabbits are killed by a disease, what will most likely happen to the fox population and the grass?

AFox increases; grass decreases
BFox decreases; grass decreases
CFox decreases; grass increases
DFox increases; grass increases
✓ Answer: C

Fewer rabbits → foxes have less food → fox population decreases. Fewer rabbits eating grass → grass population increases.

11
MCQ
MCQ1 markInquiry

A student repeats an experiment three times and gets results of 12 s, 14 s and 38 s. What should he do before calculating the mean?

AAdd all three values and divide by 3
BIdentify 38 s as an anomaly and exclude it
CRepeat the experiment only once more
DUse the middle value of 14 s as the result
✓ Answer: B

38 s is significantly different from 12 s and 14 s — it is an anomalous result. It should be identified and excluded before calculating the mean. Mean of 12 and 14 = 13 s. Including 38 would give an unrepresentative mean of 21.3 s.

12
MCQ
MCQ1 markForces

Which form of heat transfer does NOT require a medium (can travel through a vacuum)?

AConduction
BConvection
CRadiation
DConduction and convection
✓ Answer: C

Radiation transfers heat as infrared electromagnetic waves and needs no medium — this is why the Sun heats the Earth through the vacuum of space. Conduction requires particles touching. Convection requires fluid (liquid or gas) particles that can move in bulk.

13
MCQ
MCQ1 markMatter

Which separation method is best for obtaining pure water from a salt solution?

AFiltration
BEvaporation
CChromatography
DDistillation
✓ Answer: D

Distillation — the water is boiled off as steam, then condensed back to liquid, leaving the salt behind. This gives you pure water. Evaporation gives you the salt (not the water). Filtration only works for insoluble solids. Chromatography separates dissolved substances by solubility, not solvent from solution.

14
MCQ
MCQ1 markLiving

Which organelle is responsible for releasing energy through aerobic respiration?

AChloroplast
BMitochondria
CNucleus
DVacuole
✓ Answer: B

Mitochondria — the site of aerobic respiration in both plant and animal cells. Chloroplasts carry out photosynthesis (capturing light energy). The nucleus controls cell activities and contains DNA. Vacuoles store substances.

15
MCQ
MCQ1 markModels

Which statement correctly describes particles in a gas?

AParticles move rapidly and randomly in all directions with very weak forces between them
BParticles are closely packed in a regular arrangement and vibrate in fixed positions
CParticles are close together and slide past one another freely
DParticles are held by strong forces and cannot move at all
✓ Answer: A

Gas particles: far apart, random rapid motion in all directions, very weak intermolecular forces. B describes a solid. C describes a liquid. D is incorrect — even solid particles vibrate.

16
MCQ
MCQ1 markInquiry

A student wants to test whether the colour of light affects the rate of photosynthesis in a plant. She uses red, blue and white light. What is the independent variable?

AColour of light used
BRate of photosynthesis
CType of plant used
DDistance of light from plant
✓ Answer: A

The colour of light is what the student deliberately changes — the independent variable. Rate of photosynthesis is measured (DV). Type of plant and distance of light are controlled variables (kept the same).

17
MCQ
MCQ1 markForces

A car moves at constant speed on a straight, level road. Which of the following is true?

AThe driving force is greater than the friction force
BThe driving force equals the friction force
CThere is no friction acting on the car
DThe friction force is greater than the driving force
✓ Answer: B

At constant speed, forces are balanced — resultant force = 0 N. So driving force = friction force. If driving > friction (A), the car would accelerate. If friction > driving (D), the car would slow down.

18
MCQ
MCQ1 markLiving

A red blood cell has no nucleus. How does this adaptation help the red blood cell carry out its function?

AIt can control cell activities more efficiently
BIt can reproduce faster
CMore space is available to carry haemoglobin for oxygen transport
DIt can absorb oxygen through the cell wall
✓ Answer: C

Without a nucleus, the space it would have occupied is available for more haemoglobin, the protein that carries oxygen. This increases the cell's oxygen-carrying capacity. Red blood cells also have no cell wall (D is wrong — they are animal cells).

19
MCQ
MCQ1 markEnergy

A light bulb converts 100 J of electrical energy into 15 J of light and 85 J of heat. What is the efficiency of the light bulb?

A15%
B85%
C100%
D25%
✓ Answer: A

Efficiency = (useful energy out ÷ total energy in) × 100% = (15 ÷ 100) × 100% = 15%. Light is the useful output. The 85 J of heat is wasted energy. B (85%) would be the efficiency if heat were the useful output.

20
MCQ
MCQ1 markMatter

A sample of a substance melts at exactly 0°C and boils at exactly 100°C. What can be concluded about this substance?

AIt is a mixture of compounds
BIt is an element
CIt is a pure substance
DIt is definitely water
✓ Answer: C

Sharp, fixed melting and boiling points indicate a pure substance. Mixtures melt and boil over a range of temperatures. While 0°C/100°C match water, we cannot say it is "definitely" water from melting and boiling point alone — other substances could have the same values (D is too specific). A pure substance could be an element or compound, so B is not fully correct.

🔬
Inquiry & Lab Safety — Structured Questions
Write your answer, then reveal the mark scheme.
S1
Structured
Structured8 marks

A student investigates how the concentration of acid affects the rate of a reaction with marble chips. She uses acid concentrations of 0.5 mol/dm³, 1.0 mol/dm³, 1.5 mol/dm³ and 2.0 mol/dm³. She measures the volume of gas produced every 30 seconds for 3 minutes. She repeats each concentration three times.

Table of results (volume of gas in cm³ at 3 minutes):

Concentration (mol/dm³)Trial 1 (cm³)Trial 2 (cm³)Trial 3 (cm³)Mean (cm³)
0.5182019
1.0353736
1.5525170
2.0687069
  1. (a) State the independent variable and the dependent variable in this investigation. [2]
  2. (b) State two controlled variables in this investigation, giving specific values where possible. [2]
  3. (c) Identify the anomalous result in the table. Explain why it should be excluded from the mean. [2]
  4. (d) Calculate the mean volume of gas for concentration 1.5 mol/dm³, excluding the anomaly. [1]
  5. (e) State one safety precaution the student should take when using acid, and explain why. [1]
▶ Show Mark Scheme
✓ Mark Scheme
Model answers
  • (a) IV: Concentration of acid (mol/dm³) [1]. DV: Volume of gas produced (cm³) [1].
  • (b) Any two (with values): Mass/size of marble chips (e.g. 1 g); Volume of acid used (e.g. 50 cm³); Temperature of acid; Same container size / flask; Same time period (3 minutes) [1 each].
  • (c) The anomalous result is 70 cm³ at 1.5 mol/dm³, Trial 3. It is much higher than the other two readings (52 and 51 cm³) and does not fit the pattern. Including it would give an unrepresentative mean. [2]
  • (d) Mean = (52 + 51) ÷ 2 = 51.5 cm³ [1]
  • (e) Wear safety goggles [1] to protect the eyes from acid splashes / acid is corrosive and can damage the eyes. [Accept: wear gloves to protect skin from contact with acid]
Note: For (b), "same amount of acid" is too vague — must say "same volume (e.g. 50 cm³)" for the mark.
S2
Structured
Structured5 marks

A student grows cress seeds under three different conditions: in a dark cupboard, on a sunny windowsill, and under a red lamp. After one week she measures the height of the seedlings.

  1. (a) Is this a fair test? Give one reason for your answer. [2]
  2. (b) Suggest one improvement to make the investigation more reliable. [1]
  3. (c) The student concludes: "Plants grow taller in sunlight." Explain why this conclusion may not be fully supported by her evidence. [2]
▶ Show Mark Scheme
✓ Mark Scheme
Model answers
  • (a) Not a fair test [1] because the three conditions vary in more than one factor — the sunny windowsill provides both more light and potentially different temperature and humidity compared to the dark cupboard and red lamp, so it is not possible to isolate the effect of light colour / intensity alone. [1]
  • (b) Grow multiple seedlings (e.g. 5) in each condition and calculate the mean height / use identical pots, same soil, same volume of water, same temperature. [1]
  • (c) She only used three conditions — she cannot conclude sunlight specifically causes the most growth without controlling other variables (temperature, humidity) [1]. She also only measured height — taller does not necessarily mean healthier growth. [1] Accept: she only has one seedling per condition so the results may not be reliable.
S3
Open-ended
Open-ended5 marks

Design an investigation to find out how the temperature of water affects the time taken for an effervescent tablet to fully dissolve. In your answer, state the independent variable, the dependent variable, at least three controlled variables with values, and describe how you would carry out the experiment to ensure the results are reliable.

▶ Show Model Answer
✓ Model Answer
Mark scheme
  • IV: Temperature of water — e.g. 20°C, 40°C, 60°C, 80°C [1]
  • DV: Time taken for the tablet to fully dissolve (seconds), measured with a stopwatch [1]
  • CVs (any three): Volume of water (e.g. 200 cm³); same brand/type of tablet; same mass of tablet; same container (beaker); no stirring / same stirring rate [1]
  • Reliability: Repeat each temperature at least three times and calculate the mean; identify and discard anomalous results [1]
  • Method: Heat water to target temperature (verified with thermometer); add tablet; start stopwatch; stop when no solid remains; record time [1]
⚗️
Exploring Matter — Structured Questions
Elements, compounds, mixtures, changes of state and separation.
M1
Structured
Structured7 marks

Kang Wei dissolves some potassium permanganate (a purple solid) in water to form a purple solution. He then filters the solution through filter paper.

  1. (a) Is potassium permanganate dissolving in water a physical or chemical change? Give two reasons. [2]
  2. (b) What does Kang Wei observe after filtration? Explain why. [2]
  3. (c) Kang Wei wants to obtain pure potassium permanganate crystals from the purple solution. Name the separation method he should use and describe the process. [2]
  4. (d) Is potassium permanganate an element, compound or mixture? Give a reason. [1]
▶ Show Mark Scheme
✓ Mark Scheme
Model answers
  • (a) Physical change [accept implied]. Reason 1: No new substance is formed — the solution is still potassium permanganate and water. Reason 2: The change is reversible — the potassium permanganate can be recovered by evaporating the water. [1 each, max 2]
  • (b) The purple solution passes through (filtrate is purple); no residue remains on filter paper [1] because potassium permanganate is soluble — it dissolves into individual particles small enough to pass through the filter paper pores [1].
  • (c) Evaporation / crystallisation [1]. Heat the solution until most water evaporates; allow to cool so that crystals form; filter off the crystals and allow to dry [1].
  • (d) Compound [1] — it contains more than one type of element (potassium, manganese, oxygen) chemically bonded together.
M2
Structured
Structured6 marks

The diagram below shows a heating curve for a pure substance.

Heating curve description: Temperature rises from 20°C, levels off at 50°C for several minutes (section BC), rises again, then levels off at 130°C (section DE), then rises again.
  1. (a) What is the melting point of this substance? [1]
  2. (b) What is the boiling point of this substance? [1]
  3. (c) What change of state is occurring during section BC? Explain why temperature remains constant during this section even though heat is being supplied. [2]
  4. (d) A student says: "This substance must be impure because its melting point is not 0°C." Is the student correct? Explain your answer. [2]
▶ Show Mark Scheme
✓ Mark Scheme
Model answers
  • (a) 50°C [1]
  • (b) 130°C [1]
  • (c) Melting (solid → liquid) [1]. Temperature stays constant because the energy supplied is used to break the forces between particles (to change the arrangement from solid to liquid) rather than raising the temperature [1].
  • (d) The student is incorrect [1]. Pure substances have sharp fixed melting and boiling points — but these do not have to be 0°C. Only water melts at 0°C. This substance's sharp, flat melting plateau at exactly 50°C indicates it is a pure substance, not an impure one [1].
⚠ Common trap: Students often think 0°C is the melting point of all pure substances — it is only the melting point of water.
🌿
Living Diversity — Structured Questions
Cells, organelles, classification and ecology.
L1
Structured
Structured8 marks

The diagram shows two cells, X and Y.

Cell X: Irregular shape; contains nucleus, mitochondria, cytoplasm, cell membrane. No cell wall, no chloroplasts.

Cell Y: Regular rectangular shape; contains nucleus, mitochondria, cytoplasm, cell membrane, cell wall, chloroplasts, large central vacuole.
  1. (a) Identify whether Cell X is a plant or animal cell. Give two reasons. [2]
  2. (b) Name the organelle in Cell Y that carries out photosynthesis. State what photosynthesis converts light energy into. [2]
  3. (c) Name one organelle present in both cells and state its function. [2]
  4. (d) Cell Y has a large central vacuole. Explain the role of the vacuole in a plant cell. [1]
  5. (e) A student says that Cell Y could be a root hair cell. Do you agree? Give a reason. [1]
▶ Show Mark Scheme
✓ Mark Scheme
Model answers
  • (a) Animal cell [1]. Reasons (any two): Has no cell wall; has no chloroplasts; has no large central vacuole; has an irregular shape [1 each, max 1].
  • (b) Chloroplast [1]. Photosynthesis converts light energy into chemical energy (stored in glucose) [1].
  • (c) Nucleus [1] — controls cell activities / contains genetic information (DNA) [1]. Accept: mitochondria [1] — site of aerobic respiration / releases energy from glucose [1].
  • (d) Stores water and cell sap; helps maintain the shape and rigidity of the cell (turgor pressure) [1].
  • (e) Disagree [1] — root hair cells do not have chloroplasts because they are underground and receive no light for photosynthesis. Cell Y has chloroplasts, so it cannot be a root hair cell [1].
L2
Structured
Structured6 marks

The food web below shows feeding relationships in a pond ecosystem.

Pond food web:
Algae → Water fleas → Small fish → Large fish
Algae → Water fleas → Dragonfly larvae → Large fish
Algae → Snails → Large fish
  1. (a) Name the producer in this food web. Explain why it is classified as a producer. [2]
  2. (b) Name one secondary consumer in this food web. [1]
  3. (c) A disease kills most of the small fish. Predict and explain the effect on (i) water flea population, (ii) large fish population. [3]
▶ Show Mark Scheme
✓ Mark Scheme
Model answers
  • (a) Algae [1]. It is a producer because it makes its own food (glucose) through photosynthesis using light energy — it does not consume other organisms [1].
  • (b) Small fish OR dragonfly larvae [1]. (They eat primary consumers — water fleas.)
  • (c) (i) Water flea population increases [1] — fewer small fish eat them, so more water fleas survive [1].
    (ii) Large fish population may initially decrease [1] — they lose small fish as a food source. However, they can still eat dragonfly larvae and snails, so the effect may be reduced over time [accept reasonable reasoning].
Forces & Energy — Structured Questions
Weight, pressure, energy transformations and conservation.
F1
Structured
Structured8 marks

A woman of mass 60 kg is wearing stiletto heels. Each heel has an area of 1 cm² (0.0001 m²). She is also carrying a flat-soled backpack with a base area of 400 cm² (0.04 m²) containing her laptop of mass 2 kg. Gravitational field strength g = 10 N/kg.

  1. (a) Calculate the weight of the woman. [2]
  2. (b) She stands on one heel only. Calculate the pressure exerted by that one heel on the ground. [2]
  3. (c) Calculate the weight of the laptop and the pressure the backpack exerts on the woman's back. [2]
  4. (d) Why do stiletto heels sometimes damage soft flooring, while flat-soled shoes of the same person do not? Use the concept of pressure in your answer. [2]
▶ Show Mark Scheme
✓ Mark Scheme
Model answers
  • (a) Weight = mg = 60 × 10 = 600 N [1 for formula, 1 for correct answer with unit]
  • (b) P = F ÷ A = 600 ÷ 0.0001 = 6,000,000 Pa (6 MPa) [1 for substitution, 1 for answer with unit]
  • (c) Weight of laptop = 2 × 10 = 20 N [1]. Pressure = 20 ÷ 0.04 = 500 Pa [1]
  • (d) The stiletto heel has a very small contact area (1 cm²) [1]. The same force (woman's weight) concentrated on a tiny area creates very high pressure, which exceeds the strength of soft flooring and causes damage. A flat-soled shoe distributes the same force over a much larger area, so the pressure is much lower and does not damage the floor [1].
F2
Open-ended
Open-ended6 marks

A rollercoaster car starts from rest at the top of a hill 40 m above the ground. It rolls down without a motor and reaches the bottom. Explain the energy changes that take place from the top of the hill to the bottom, and explain why the car does not reach the same height if it goes up another hill on the other side. Use the concept of conservation of energy in your answer.

▶ Show Model Answer
✓ Model Answer
Mark scheme (6 marks)
  • At the top, the car has maximum gravitational potential energy (GPE) and zero kinetic energy (at rest). [1]
  • As the car rolls down, GPE is converted to kinetic energy (KE) — the car speeds up. [1]
  • At the bottom, most GPE has been converted to KE (maximum speed). [1]
  • Some energy is also converted to thermal energy and sound due to friction between the wheels and track and air resistance throughout the journey. [1]
  • By the law of conservation of energy, energy cannot be created or destroyed — the total energy remains constant. [1]
  • The car does not reach the same height on the other side because some energy has been lost as thermal energy and sound (wasted). The car only has enough KE at the bottom to convert back to GPE to reach a lower height than where it started. [1]
🎯
Mixed & Challenge Questions
Cross-topic questions and harder application — typical of SA paper Section C.
C1
Challenge
Open-ended8 marks★ Higher order

A student notices that wet clothes dry faster on a windy day than on a still day, even when the temperature is the same. She also notices they dry faster in sunlight than in shade at the same wind speed.

  1. (a) Name the change of state that occurs when wet clothes dry. Is energy absorbed or released? [2]
  2. (b) Design a controlled investigation to test whether wind speed affects drying time. State your IV, DV, three CVs and how you would measure the DV. [4]
  3. (c) Using your knowledge of particles, explain why sunlight helps clothes dry faster. [2]
▶ Show Model Answer
✓ Model Answer
Mark scheme
  • (a) Evaporation (liquid water → water vapour / gas) [1]. Energy is absorbed from the clothes and surroundings [1].
  • (b) IV: Wind speed (e.g. using a fan at low, medium, high settings) [1]. DV: Time for clothes to dry completely / mass loss of wet cloth over time (measured with a balance) [1]. CVs (any three): Same mass/type of cloth; same initial amount of water; same temperature; same humidity; same surface area of cloth exposed [1]. Method: Weigh wet cloth, place in wind at set speed, reweigh at regular intervals until no further mass loss [1].
  • (c) Sunlight provides energy (light and infrared radiation) to the water molecules on the surface of the clothes [1]. This extra energy allows more water molecules to overcome the forces holding them in the liquid state and escape into the air as vapour — increasing the rate of evaporation [1].
C2
Challenge
Open-ended6 marks★ Higher order

A scientist discovers a new organism in a Singapore reservoir. It is single-celled, has a nucleus, makes its own food using light energy, and can move by waving tiny hair-like structures. A classmate says it must be a plant. Evaluate this claim using your knowledge of classification.

▶ Show Model Answer
✓ Model Answer
Mark scheme (6 marks)
  • The classmate is not correct / the claim is not fully supported. [1]
  • Plants are multicellular — this organism is single-celled, so it does not fit the plant kingdom. [1]
  • Plants cannot move independently — this organism can move using hair-like structures (cilia/flagella). [1]
  • The organism has a nucleus (eukaryotic) — this rules out bacteria (Monera). [1]
  • It makes its own food through photosynthesis — this is a characteristic shared with plants but also with some protists (e.g. algae). [1]
  • Based on all its characteristics (unicellular, has nucleus, autotrophic, motile), this organism is most likely a protist (e.g. similar to Euglena or an alga). [1]
C3
Challenge
Structured5 marks★ Calculation chain

An electric motor takes in 500 J of electrical energy per second. It produces 350 J of kinetic energy and wastes the rest as thermal energy and sound.

  1. (a) How much energy is wasted per second? [1]
  2. (b) Calculate the efficiency of the motor. [2]
  3. (c) State the law of conservation of energy and use it to explain why the efficiency cannot be 100%. [2]
▶ Show Mark Scheme
✓ Mark Scheme
Model answers
  • (a) Energy wasted = 500 − 350 = 150 J per second [1]
  • (b) Efficiency = (350 ÷ 500) × 100% = 70% [1 for formula, 1 for correct answer]
  • (c) The law of conservation of energy states that energy cannot be created or destroyed — it can only be transformed from one form to another [1]. In any real machine, some energy is always transformed into thermal energy due to friction and resistance. This energy is not useful output — it is wasted. Therefore the useful output is always less than the total input, and efficiency is always less than 100% [1].

Go deeper — full study notes